Biology 100/101
Take-home Assignment
#5 Human Genetics

Fall 2008 (20 Points)
Due At Lecture Monday,
October 20

Your Name ________________________
Course (100 or 101) ________________________
Your TA's Name ________________________

Please TYPE your answers on separate paper and attach this sheet as a cover sheet. Drawings may be neatly hand rendered and hand labeled. Read and sign the academic integrity statement below.

NOTE: We encourage people to work and study together, but the final product should be an INDIVIDUAL effort. Discuss and talk over questions together, but write up your answers by yourself after the study session. When you use diagrams or concept maps, create your own rather copying those from the text or lecture materials. Definitions and explanations should be in your words and not those of the text book author or any other source.

Your job is to convince your instructor that YOU understand these ideas.

Work copied from others will not be accepted. Because answers will be posted on the web immediately after the due time, late work will not be accepted.

Academic Integrity in Biology 100/101

I have read and understand Part #4 of the University of Illinois Student Code, which deals with Academic Integrity.

Signature

_______________________________________


Please use the "Talk to Sarah and Ed" Forum in Moodle if you wish to discuss the assignment further.

Answers will be linked to the Take-Home Assignment web page shortly after this assignment is due.

Don't overlook the links to web resources and references to text pages below that might be useful in answering these questions. Activities in lecture, discussion, and laboratory classes will also address these questions.


Completion of these questions will help you achieve most of the objectives for lectures #11, #12, and #13

Question #1. Autosomal Recessive Trait (5 points)

Tay-Sachs disease is an autosomal recessive disorder that results in a degeneration of the nervous system, producing symptoms at about 6 months of age. Affected children loose hearing, sight, and the ability to move. Children with Tay-Sachs disease normally die by age 3.

The gene involved in this disease is HEXA, located on chromosome #15 (8th from the bottom of the right-hand list of gene locations). The normal, dominant allele for the HEXA gene codes for the alpha subunit of the enzyme β-hexosaminidase. The HEXA enzyme is packaged in the lysosomes of nerve cells and breaks down a fatty material called GM2 ganglioside. This fatty material builds up and degrades the nerve cells of a person who has two recessive alleles for the HEXA gene locus.

A couple are interested in having a child, but have learned that the man is a carrier for the disease and the woman is homozygous dominant. What is the chance that their first child will be born a carrier of Tay-Sachs disease?

Show how you arrived at your answer.

Watch segment 3 of the PBS "Nova" program, "Cracking The Code of Life" - "One Wrong Letter". This is an interesting case study of a couple dealing with Tay-Sachs disease

Question #2. Autosomal Dominant Trait (5 points)

Huntington disease is caused by an autosomal dominant mutant allele that produces an abnormally long version of a protein normally present in the brain. The result is a degeneration of nerve function causing loss of motor control and personality changes, ultimately leading to death. The symptoms do not become apparent until a person is in his or her 40s. See also Huntington's Disease Society of America

The gene associated with Huntington disease is located on chromosome #4. The protein that is produced by the gene is "huntingtin". The mutation adds repeated triplets of nucleotides to the gene and produces a longer than normal protein with enhanced, abnormal function. The mutant protein produced by the mutated dominant allele overshadows the function of the normal protein produced by the recessive allele.

A person in her teens learns that her father is developing symptoms of Huntington disease. Her father is heterozygous. Her mother is normal (homozygous recessive). What is the chance that the young woman will never develop Huntington disease as she becomes older?

Show how you arrived at your answer.

Question #3. Aneuploidy and Nondisjunction (5 points)

XYY Syndrome (47 XYY) results when a person inherits two sex chromosomes from one of his parents, and a third from the other parent, resulting in a condition in which the individual has three sex chromosomes (an X and 2 Y chromosomes). The affected individual develops as a male. Individuals with this condition generally are of taller stature and may have acne. Some boys with XYY syndrome are physically more active and may have delayed mental maturation.

More information about XYY Syndrome:

See the "Abnormal chromosome numbers" section of lecture outline #12 for more information on aneuploidy and nondisjunction.

Question #4. Two Gene Genetics and X-linkage (5 points)

Autosomal Recesive

In the mountains of eastern Kentucky there is a small rural community called Troublesome Creek that includes a significant number of people who have a decided blue cast to their skin with very blue lips. Hereditary methemoglobinemia (met-H) is a human genetic disease that is inherited as an autosomal recessive disorder. The gene is located on chromosome 22 (Last gene on the right hand list).

The condition is a result of a missing enzyme called NADH diaphorase (DIA1). The diaphorase enzyme essentially recycles a person's hemoglobin molecules. The iron contained in hemoglobin must be in a reduced state in order to carry oxygen. Once oxygen has been added, the iron in the hemoglobin becomes oxidized. The diaphorase enzyme normally reduces the iron in hemoglobin making it possible for the hemoglobin to pick up more oxygen. In people with two recessive alleles for this enzyme the hemoglobin is much more slowly reduced. The blue color of the affected person's skin is due to the reduced level of oxygen in their blood.

Sex-linked Recesive (X chromosome)

Severe combined immunodeficiency (SCID) is an X-linked recessive disorder. Affected individuals have little or no immune response. You may have heard about the condition as "bubble boy disease". With no immune system, a person is susceptible to recurrent infections from many common diseases that most of us consider minor. A mutated, recessive gene fails to produce an interleukin receptor protein that is necessary for the immune system to function and protect a person from common pathogens.

A man and a woman are having a child.

The man is a carrier (heterozygous) for met-H and does NOT have SCID.

The woman is also a carrier for met-H. The woman's father has SCID disease. The woman's mother is homozygous dominant for the SCID gene locus.

What is the probability that their child will be a boy who has met-H AND SCID? Show how you arrived at your answer.