), indicating that the reaction is reversible. Since in principle all reactions are microscopically reversible, this is generally appropriate, even when the equilibrium constant is very large.
glucose-6-P + ADP
2lactate + 2ATPIn general:
pP
However, use of the term "overall order of reaction" is a little muddled, because it is generally recognized as an empirical term, so that the value found by experiment might not correspond to that expected by applying the above general rule. Most frequently, for simple chemical processes, the order of reaction found experimentally turns out to be equal to the sum of the stoichiometric coefficients of the reactants. This is generally the case for reactions with a large Keq, starting from the condition of [P] = 0, since [P] will then be negligible during the time of measurement, and the reverse reaction will not be significant. Then, for the general reaction above:
For most biochemical processes, enzyme catalysis and the saturation effects resulting from this, determine that the steady-state reaction does not obey the simple rules. However, if the pre-steady-state kinetics are measured, in which the enzyme is considered as a reactant, then the simple rate laws pertain. We will examine this case separately in a later lecture.
While the overall order of reaction is described as above, a second term is also often used, - the order of reaction with respect to a particular species. For example, in a reaction involving 2A, the reaction is said to be 2nd.-order in A. The order is given simply by the stoichiometric ratio. From this it can be seen that measurement of the order of reaction can provide a value for the coefficient if this is otherwise unknown. A useful protocol for determining the order of reaction with respect to a particular component is to measure the concentration dependence of rate when all other reactants are in great excess. Under these circumstances, their concentrations will not vary significantly during the reaction, and the rate law revealed by experiment will give the order of reaction with respect to the tested component:
v = k'[B]b
k' = k[A]aexcess
P*A
P+A-
PA
PA
rate of reaction = v = -d[P+A-]/dt = k1[P+A-]
Another case of general interest is found in all enzyme catalyzed reactions. In simple Michaelis-Menton kinetics, the reaction procedes through two steps, - formation of the enzyme-substrate (ES-) complex, and followed by the breakdown of the ES-complex to products:
ES
E + PFor the general case , we will consider a 1st-order reaction:
B








Finally, a useful term allowing comparison of rates for different processes is the the half-time for the process, t½, - the time for half completion of the reaction. A similar term is also commonly used in the context of radioactive decay, to specify the half-life of a radioactive species. We can derive an equation for t½ by substitution into the above, as follows:
t½ = 0.6931 / k1
Note that the concentration of [A] does not appear in this equation, - the half-time of the reaction is independent of the starting concentration.
While reactions involving a single species with a stoichiometric coefficient of 2 are quite common in chemistry, they are relatively rare in biochemistry. An interesting example from earlier in the course is the mechanism of action of gramicidin. When this ionophore forms a pore across a biological membrane, two monomers (M) interact in the membrane to form the active dimeric form (D). The frequency of formation of active dimers can be assayed by measuring the current across a black lipid membrane, - the current jump when a single channel forms can be readily detected. It is found that the probability of formation of channels is proportional to [M]2
D
Derivation of the formal equations describing this sort of reaction follows a similar approach to that for 1st-order reactions. We describe a general reaction:
P
We chose a set of parameters to minimize terms:







Note that the integrated rate equation shows that a plot of 1 / [A] against time will give a straight line for a 2nd-order, Class I reaction, with an intercept at 1 / [A]0. Note also that a concentration term for [A] appears in the equation for t½, so the half-time depends on initial concentration.
As noted above, for most enzyme catalyzed reactions, the formation of the enzyme-substrate complex (ES-complex) involves a collisional reaction between substrate and enzyme. This can be considered as a 2nd-order reaction of Class II, in which the substrate and enzyme are reactants, and the ES-complex is the product.
ES
Again, derivation of the formal equations describing this sort of reaction follows a similar approach to that for 2nd-order reactions of Class I. However, because the reactants can have initial concentrations that are different, the formalism differs from that for Class I reactions. As noted below, in the special case that the initial concentrations of the two reactants is the same, this formalism fails, but in that case the equations derived for Class I reactions can be applied.
First, we describe a general reaction:
P
We would like to chose a set of parameters to minimize terms, but are now stuck with the participation of the second reactant, and therefore have to include an appropriate concentration term.



Note that the integrated rate equation shows that a plot of ln [A]/[B] against time will give a straight line for a 2nd-order, Class II reaction. Note also that the treatment fails if the initial concentrations of the two substrates are the same, - the logarithmic term becomes zero. In this case, the reaction can be treated by the same formalism as for Class I reactions, or alternatively, the initial concentrations can be handle if the values are very slightly different.